作业帮这是一道线性代数题.求一组R^4空间的正交基,第一个基向量与u平行.In the space R^4 form an orthogonal basis such that the first basis vector is parallel to the vector u=(0,-3,0,4).
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这是一道线性代数题.求一组R^4空间的正交基,第一个基向量与u平行.In the space R^4 form an orthogonal basis such that the first basis vector is parallel to the vector u=(0,-3,0,4).
这是一道线性代数题.求一组R^4空间的正交基,第一个基向量与u平行.
In the space R^4 form an orthogonal basis such that the first basis vector is parallel to the vector u=(0,-3,0,4).
这是一道线性代数题.求一组R^4空间的正交基,第一个基向量与u平行.In the space R^4 form an orthogonal basis such that the first basis vector is parallel to the vector u=(0,-3,0,4).
这样的解很多的,下面我构造(注意是造)其中一组R^4空间的单位正交向量组.
e1,we have known e1//u;
we let e2=(0,4,0,3),and it content (e1⊥e2)
then,let e3=(1,0,1,0),it content (e3⊥e1,e3⊥e2)
At last,let e4=(-1,0,1,0),e4 content (e4⊥e1,e4⊥e2,e4⊥e3)
And then,get them to be basis vector
e1=(0,-3/√5,0,4/√5)
e2=(0,4/√5,0,3/√5)
e3=(1/√2,0,1/√2,0)
e4=(-1/√2,0,1/√2,0)
This is only one solution and or course,there are other solutions .
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