lingo问题,谁帮我运行下这个程序,有错误的话帮我看看model:sets:xcs/1..20/:A,m,n,q;ccs/1..2/:x;link(xcs,ccs):c,b;endsetsdata:A=300,320,340,360,380,400,440,460,500,540,480,440,380,340,280,200,160,80,60,40;m=16,16,16,16,16,16,16,16,16,

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lingo问题,谁帮我运行下这个程序,有错误的话帮我看看model:sets:xcs/1..20/:A,m,n,q;ccs/1..2/:x;link(xcs,ccs):c,b;endsetsdata:A=300,320,340,360,380,400,440,460,500,540,480,440,380,340,280,200,160,80,60,40;m=16,16,16,16,16,16,16,16,16,
lingo问题,谁帮我运行下这个程序,有错误的话帮我看看
model:
sets:
xcs/1..20/:A,m,n,q;
ccs/1..2/:x;
link(xcs,ccs):c,b;
endsets
data:
A=300,320,340,360,380,400,440,460,500,540,480,440,380,340,280,200,160,80,60,40;
m=16,16,16,16,16,16,16,16,16,16,16,16,16,16,16,16,16,16,16,16;
n=8,8,8,16,16,16,16,16,16,16,16,16,16,16,16,16,16,16,16,16;
q=1,1,1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2;
enddata
min=@sum(ccs(j):x(j));
x(1)=0;
@for(ccs(j):@gin(x(j)));
@for(xcs(i):m(i)*x(1)+@sum(link(i,j):2*c(i,j)*x(1))+n(i)*x(2)+@sum(link(i,j):q(i)*b(i,j)*x(2))>=A(i));
@for(link(i,j):@bin(c(i,j)));
@for(link(i,j):@bin(b(i,j)));
end

lingo问题,谁帮我运行下这个程序,有错误的话帮我看看model:sets:xcs/1..20/:A,m,n,q;ccs/1..2/:x;link(xcs,ccs):c,b;endsetsdata:A=300,320,340,360,380,400,440,460,500,540,480,440,380,340,280,200,160,80,60,40;m=16,16,16,16,16,16,16,16,16,
没语法错误结果
Local optimal solution found.
Objective value: 31.00000
Objective bound: 31.00000
Infeasibilities: 0.000000
Extended solver steps: 11
Total solver iterations: 203
Variable Value
A( 1) 300.0000
A( 2) 320.0000
A( 3) 340.0000
A( 4) 360.0000
A( 5) 380.0000
A( 6) 400.0000
A( 7) 440.0000
A( 8) 460.0000
A( 9) 500.0000
A( 10) 540.0000
A( 11) 480.0000
A( 12) 440.0000
A( 13) 380.0000
A( 14) 340.0000
A( 15) 280.0000
A( 16) 200.0000
A( 17) 160.0000
A( 18) 80.00000
A( 19) 60.00000
A( 20) 40.00000
M( 1) 16.00000
M( 2) 16.00000
M( 3) 16.00000
M( 4) 16.00000
M( 5) 16.00000
M( 6) 16.00000
M( 7) 16.00000
M( 8) 16.00000
M( 9) 16.00000
M( 10) 16.00000
M( 11) 16.00000
M( 12) 16.00000
M( 13) 16.00000
M( 14) 16.00000
M( 15) 16.00000
M( 16) 16.00000
M( 17) 16.00000
M( 18) 16.00000
M( 19) 16.00000
M( 20) 16.00000
N( 1) 8.000000
N( 2) 8.000000
N( 3) 8.000000
N( 4) 16.00000
N( 5) 16.00000
N( 6) 16.00000
N( 7) 16.00000
N( 8) 16.00000
N( 9) 16.00000
N( 10) 16.00000
N( 11) 16.00000
N( 12) 16.00000
N( 13) 16.00000
N( 14) 16.00000
N( 15) 16.00000
N( 16) 16.00000
N( 17) 16.00000
N( 18) 16.00000
N( 19) 16.00000
N( 20) 16.00000
Q( 1) 1.000000
Q( 2) 1.000000
Q( 3) 1.000000
Q( 4) 2.000000
Q( 5) 2.000000
Q( 6) 2.000000
Q( 7) 2.000000
Q( 8) 2.000000
Q( 9) 2.000000
Q( 10) 2.000000
Q( 11) 2.000000
Q( 12) 2.000000
Q( 13) 2.000000
Q( 14) 2.000000
Q( 15) 2.000000
Q( 16) 2.000000
Q( 17) 2.000000
Q( 18) 2.000000
Q( 19) 2.000000
Q( 20) 2.000000
X( 1) 3.000000
X( 2) 28.00000
C( 1, 1) 1.000000
C( 1, 2) 1.000000
C( 2, 1) 1.000000
C( 2, 2) 1.000000
C( 3, 1) 1.000000
C( 3, 2) 1.000000
C( 4, 1) 1.000000
C( 4, 2) 1.000000
C( 5, 1) 1.000000
C( 5, 2) 1.000000
C( 6, 1) 1.000000
C( 6, 2) 1.000000
C( 7, 1) 1.000000
C( 7, 2) 1.000000
C( 8, 1) 1.000000
C( 8, 2) 1.000000
C( 9, 1) 1.000000
C( 9, 2) 0.000000
C( 10, 1) 0.000000
C( 10, 2) 0.000000
C( 11, 1) 1.000000
C( 11, 2) 1.000000
C( 12, 1) 1.000000
C( 12, 2) 1.000000
C( 13, 1) 1.000000
C( 13, 2) 1.000000
C( 14, 1) 1.000000
C( 14, 2) 1.000000
C( 15, 1) 1.000000
C( 15, 2) 1.000000
C( 16, 1) 1.000000
C( 16, 2) 1.000000
C( 17, 1) 1.000000
C( 17, 2) 1.000000
C( 18, 1) 1.000000
C( 18, 2) 1.000000
C( 19, 1) 1.000000
C( 19, 2) 1.000000
C( 20, 1) 1.000000
C( 20, 2) 1.000000
B( 1, 1) 1.000000
B( 1, 2) 1.000000
B( 2, 1) 1.000000
B( 2, 2) 1.000000
B( 3, 1) 1.000000
B( 3, 2) 1.000000
B( 4, 1) 1.000000
B( 4, 2) 1.000000
B( 5, 1) 1.000000
B( 5, 2) 1.000000
B( 6, 1) 1.000000
B( 6, 2) 1.000000
B( 7, 1) 1.000000
B( 7, 2) 1.000000
B( 8, 1) 1.000000
B( 8, 2) 1.000000
B( 9, 1) 0.000000
B( 9, 2) 0.000000
B( 10, 1) 0.000000
B( 10, 2) 1.000000
B( 11, 1) 1.000000
B( 11, 2) 1.000000
B( 12, 1) 1.000000
B( 12, 2) 1.000000
B( 13, 1) 1.000000
B( 13, 2) 1.000000
B( 14, 1) 1.000000
B( 14, 2) 1.000000
B( 15, 1) 1.000000
B( 15, 2) 1.000000
B( 16, 1) 1.000000
B( 16, 2) 1.000000
B( 17, 1) 1.000000
B( 17, 2) 1.000000
B( 18, 1) 1.000000
B( 18, 2) 1.000000
B( 19, 1) 1.000000
B( 19, 2) 1.000000
B( 20, 1) 1.000000
B( 20, 2) 1.000000
Row Slack or Surplus
1 31.00000
2 0.000000
3 28.00000
4 40.00000
5 20.00000
6 0.000000
7 260.0000
8 240.0000
9 220.0000
10 180.0000
11 160.0000
12 2.000000
13 12.00000
14 140.0000
15 180.0000
16 240.0000
17 280.0000
18 340.0000
19 420.0000
20 460.0000
21 540.0000
22 560.0000
23 580.0000

lingo问题,谁帮我运行下这个程序,有错误的话帮我看看model:sets:xcs/1..20/:A,m,n,q;ccs/1..2/:x;link(xcs,ccs):c,b;endsetsdata:A=300,320,340,360,380,400,440,460,500,540,480,440,380,340,280,200,160,80,60,40;m=16,16,16,16,16,16,16,16,16, lingo程序如何运行哪位好心人帮我运行下程序啊,一定好评! 哪位好心人能帮我用LINGO编一下这个程序.谢谢! 50分在线等34*34矩阵TSP问题matlab或lingo程序求一个34*34矩阵的TSP问题的MATLAB或者lingo的程序均可.有会的联系我我传矩阵过去.如果如数正确能运行处最佳解,加赏剩余分数. 请高手帮我找下这个Lingo程序的错误!下面是Lingo程序model:sets:hotel/1..10/;format/1..3/;link(hotel,format):x,y,c;endsetsmin=@sum(link:x*y*c);@for(format(j):@sum(hotel(i):(y(i)*r(i,j)))=num(j)/2);@for(format(j):@sum(hotel(i):(y(i)*r1( lingo计算结果Too many inequality or equality relation提示麻烦哪位大神帮我看一下这个程序有什么问题,为什么会有Too many inequality or equality relation提示?min=2.77*10^(-6)*(2.6*10^6*x1+5.87*10^7*x2+3.57*10^7*x3+1.37*10^ model: min=800*x11+1000*x12+1200*x13+700*x21+500*x22+700*x23+800*x31+600*x32+500*x33+500*x41+600*x4哪位可以帮忙看下这个lingo程序有什么问题?为什么我把它求出的变量值带入目标函数得到的结果和它自动求出的目大神帮我看看这个matlab程序实现的拉格朗日插值程序计算运行为什么有问题?%Lagrange interpolationfunction y=lagrange(x0,y0,x)n=length(x0); m=length(x);for i=1:m z=x(i); s=0.0; for k=1:n p=1.0; for j=1: 大家能帮忙看看这个lingo程序哪里有问题吗?新手很艰难啊,请大家简洁一点说,运行之后总是出现error code 24,说z1是invalid set namemodel:sets:error/1..4/:z1,z2;weight/1..4/:w;datas/1..4/:d1;link(datas,datas):dd,aa;ends 为什么这个lingo程序运行不成功,我希望能够在满足以下四个约束条件的情况下得到一个32*40的0-1矩阵~model:sets:a/1..32/:c; b/1..40/; link(a,b):e;endsetsdata:c=1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 有没有哪个好心人可以帮我运行一下这个JAVA程序?告诉我运行的结果是什么样.import java.awt.*;import java.awt.event.*;import javax.swing.*;import javax.swing.border.*;public class GRIDRAWING{public static void main(String ar 有哪位高手会操作LINGO,帮我写一下运行下面的程序,很着急的,：s对长：Ls等待对长：Lp平均等待时间：Wq逗留时间：Ws1/λ:表示相邻两顾客到达平均时间1/μ:表示对每个顾客平均服务时间运用到菜鸟求lingo下题程序谁帮我看下我有没有问题! 帮我运行个lingo的程序,我这边运行不了程序如下：model:sets:cities/1..6/:u; link(cities,cities):dist,x;endsetsn=@size(cities);data:dist=0 5600 3500 2100 5100 60005600 0 2100 5700 7800 70003500 2100 0 3600 6800 68002100 5700 3600 0 51 哪位大神能帮我把这个程序注释一下,我只知道程序运行结果!/* Includes ------------------------------------------------------------------*/#include stm32f10x_lib.h/* Private typedef --------------------------------------------- 要求：用Lingo软件解决如下问题,要求每道计算题有问题的符号说明、问题的建模、模型的Lingo求解程序、运行结果.某医院根据日常工作统计,每昼夜24小时中至少需要下列数量的护士.序号时