作业帮已知实数x,y满足(x-3)^2+(y+2)^2=4,求根号[x^2+(y+1)^2]的最大值
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![已知实数x,y满足(x-3)^2+(y+2)^2=4,求根号[x^2+(y+1)^2]的最大值](/uploads/image/z/6109677-45-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B3%28x-3%29%5E2%2B%28y%2B2%29%5E2%3D4%2C%E6%B1%82%E6%A0%B9%E5%8F%B7%5Bx%5E2%2B%28y%2B1%29%5E2%5D%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC)
已知实数x,y满足(x-3)^2+(y+2)^2=4,求根号[x^2+(y+1)^2]的最大值
已知实数x,y满足(x-3)^2+(y+2)^2=4,求根号[x^2+(y+1)^2]的最大值
已知实数x,y满足(x-3)^2+(y+2)^2=4,求根号[x^2+(y+1)^2]的最大值
题意即半径为2,圆心在(3,-2)的圆上的点,到(0,-1)的最大距离
做图,连接圆心与(0,-1)交圆,得最大与最小,剩下的自己算吧,勾股定理
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