sin^2 x+sinxcosx化简求化简后单调递减区间

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sin^2 x+sinxcosx化简求化简后单调递减区间

sin^2 x+sinxcosx化简求化简后单调递减区间
sin^2 x+sinxcosx化简
求化简后单调递减区间

sin^2 x+sinxcosx化简求化简后单调递减区间
sin^2 x+sinxcosx=(1-cos2x)/2+(sin2x)/2=1/2+(1/2)(sin2x-cos2x)=1/2+(√2/2){[(√2)/2]sin2x-[(√2)/2]cos2x}
=1/2+(√2/2)sin(2x+π/4)

cos^2+2sinxcosx+sin^2x sin 2x为何等于2sinxcosx sin²X-sinXcosX 求化简! f(x)=sin^2x+sinxcosx-1/2,化简 y=(cos^2x)/(sinxcosx-sin^2x),(0 sin²X-sinxcosx+2cos²x=化简 sin²x+sinxcosx+2cos²x= f(x)=sin^2x+sinxcosx 如何化简 化简cos^4x-2sinxcosx-sin^4x 2sin平方x +cos平方x+3sinxcosx化简 求证 1+2sinxcosx/sin^2x-cos^2x=sin^2x-cos^2x/1-2sinxcosx 证明1-2sinxcosx/cos^2x-sin^2x=cos^2x-sin^2/1+2sinxcosx 2sin^2x-sinxcosx-cos^2=1 2根号3sinxcosx+2sin^2x的值域 sin^2xtanx+cos^2x/tanx+2sinxcosx-(1+cosx/sinxcosx)化简 sin^2xtanx+(cos^2x/tanx)+2sinxcosx-1+cos/sinxcosx 求y=sin^2x+2sinxcosx的周期 已知tanx 2 则sin^2x-sinxcosx