[X+Y]的平方-Y〔2X+Y)-8X〕除以2X

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[X+Y]的平方-Y〔2X+Y)-8X〕除以2X

[X+Y]的平方-Y〔2X+Y)-8X〕除以2X
[X+Y]的平方-Y〔2X+Y)-8X〕除以2X

[X+Y]的平方-Y〔2X+Y)-8X〕除以2X
[X+Y]的平方-Y〔2X+Y)-8X〕除以2X
=[(x^2+2xy+y^2)-(2xy+y^2)-8x]/2x
=[x^2-8x]/2x
=x/2-4
=(1/2*x)-4

(X+Y)的平方-Y〔2X+Y)-8X
=x^2+2xy+y^2-2xy-y^2-8x
=x^2-8x
除以2X
(x^2-8x)/2x
=x/2-4

[X+Y]的平方-Y〔2X+Y)-8X〕=(X^2+2XY+Y^2-Y^2-2XY-8X)=(X^2-8X)\
除以2X 原始=X/2-4

求解; [X+Y]的平方-Y〔2X+Y)-8X〕除以2X
[(X+Y)(X+Y)-Y〔2X+Y)-8X]/2X
=(XX+2XY+YY-2XY-YY-8X)/2X
=(XX-8X)/2X
=X/2-2

=[x^2+2xy+y^2-2xy-y^2-8x]÷2x
=(x^2-8x)÷2x
=x(x-8)÷2x
当x≠0时,
=x/2-4