作业帮求2sin(-1110°)-sin960°+根号2cos(-225°)-cos(-210°)
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求2sin(-1110°)-sin960°+根号2cos(-225°)-cos(-210°)
求2sin(-1110°)-sin960°+根号2cos(-225°)-cos(-210°)
求2sin(-1110°)-sin960°+根号2cos(-225°)-cos(-210°)
2sin(-1110°)-sin960°+根号2cos(-225°)-cos(-210°)
=2sin(-30-3*360)-sin(360*3-120)+根号2cos(135)-cos150
=2*(-1/2)-(-（根号3）/2）+（根号2）*（-根号2）/2-（-（根号3）/2）
=-1+根号3-1=-2+根号3
-2+（根三）/2
原式=2sin(11/6π-4π)-sin(4/3π+2π)+根号2cos(3/4π-2π)-cos(5/6π-2π)
=2sin(11/6π)-sin(4/3π)+根号2cos(3/4π)-cos(5/6π)
=-2sin(5/6π)+sin(1/3π)-根号2sin(1/4π)+sin(1/3π)
=-2cos(1/3π)+sin(1/3π)-根号2sin(1/4π)+sin(1/3π)
=-1/2×2+√3/2-1+√3/2
=√3-2
求2sin(-1110°)-sin960°+根号2cos(-225°)-cos(-210°)
求2sin(-1110°）-sin960°+√2cos(-225°）+cos(-210°）详细步骤,
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