2log5(25)+3log2(64)请使用换底公式解决

lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) ) 2log5(25)+3log2(64)请使用换底公式解决 2log5(25)-3log2(64) 如题`怎么做? 2log5^25–3log2^64等于? 2log5(25)+3log2(64)-8ln1等于多少 2log5 25＋3log2 64等于多少 2log5(底数) 25+3log2(底数) 64-8log2 (底数)1的值为是多少, 2log5 10+log5 0.25= 2log5 25-3log2 64= log2(log2 16)= 已知lg2=a,lg3=b,求log3 4,log2 12 2log5(底)25-3log2(底)64求解 log2(底)(log2(底)32-log2(底)3/4+log2(底)6 2^(1/2log2 3)+(1/25)^log5 3= log3 25×log2 27×log5 2^-3=_____ 2log5(25)-3log2(64)=?注意：5和2对数的底数 2log5(底数) 25+3log2(底数) 64-8log7 (底数)1的值为是多少, (log3^4+log5^2)(log2^9+log2^根号3) (log5(10))^3-(log5(2))^3-3log5(10)*log2(5) 1.lg1/4-lg25=?2.2log5(底数)10+log5(底数)0.25=?3.2log5(底数)25-3log2(底数)64=?4.log2(底数)(log2(底)16)=? log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X 对数算术问题!求下列的值(1)6分之1 log2 64 +2分之1 log8 64 +log3 81(2)lg5分之1-2lg 根号0.2-log5 25*log5 2(3)log5 3分之1+2log2分之1*根号2-log3 27分之1-log5 15分之1(4)(log2 5+log4 0.2)*(log5 2 +log25 0.5)会做的帮下拉 !