=SUM(MAX((E10-2000)*0.05*{1,2,3,4,5,6,7,8,9}-25*{0,1,5,15,55,135,255,415,615},0),0)怎么理解?

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=SUM(MAX((E10-2000)*0.05*{1,2,3,4,5,6,7,8,9}-25*{0,1,5,15,55,135,255,415,615},0),0)怎么理解?

=SUM(MAX((E10-2000)*0.05*{1,2,3,4,5,6,7,8,9}-25*{0,1,5,15,55,135,255,415,615},0),0)怎么理解?
=SUM(MAX((E10-2000)*0.05*{1,2,3,4,5,6,7,8,9}-25*{0,1,5,15,55,135,255,415,615},0),0)怎么理解?

=SUM(MAX((E10-2000)*0.05*{1,2,3,4,5,6,7,8,9}-25*{0,1,5,15,55,135,255,415,615},0),0)怎么理解?
单元格E10是税前工资所得,如果向下填充的话,E列就是税前工资所得.=MAX((E10-2000)*0.05*{1,2,3,4,5,6,7,8,9}-25*{0,1,5,15,55,135,255,415,615},0)是个人所得税计算公式,等同于IF嵌套函数,=IF((E10-2000)

=SUM(MAX((E10-2000)*0.05*{1,2,3,4,5,6,7,8,9}-25*{0,1,5,15,55,135,255,415,615},0),0)怎么理解? sum-=max+min; matlab if abs(max(max(p(:,:,t))))>1e10 p(:,:,k)=p(:,:,k)/1000; =IF(E10 =SUM(D3:J3)-MAX(D3:J3)-MIN(D3:J3)这个公式也行 函数=sum(10,max(2,min(4,1),3)的值为 =(SUM(A1:A10)-MAX(A1:A10)-MIN(A1:A10))/(COUNT(A1:A10)-2)是什么意思 c逻辑错误还是语法错误#includestdio.hvoid main(){float max,a,min,sum=0,i;scanf(%d,&a);if(a!=-1){max=a;min=a;sum=a;} printf(%f %f %f %f,sum,i,max,min);while(a==-1){scanf(%d,&a);if(a!=-1){sum=sum+a;if(a>max)max=a;if(a C预言 #include main() { int sum=1,i;for(i=1;imax);max=b;if(c>max);max=c;if(d>max);max=d;printf(max=%d ,max);}运行结果为max=0 这个又是为什么?】 这个公式怎么通不过:TR := SUM(MAX(MAX(HIGH-LOW,ABS(HIGH-REF(CLOSE,1))),ABS(LOW-REF(CLOSE,1)))TR := SUM(MAX(MAX(HIGH-LOW,ABS(HIGH-REF(CLOSE,1))),ABS(LOW-REF(CLOSE,1))),N);HD := HIGH-REF(HIGH,1);LD := REF(LOW,1)-LOW;DMP:= SUM(IF(HD>0 AND HD>L 请问有没有未来函数VAR1:=SUM(MAX(MAX(HIGH-LOW,ABS(HIGH-REF(CLOSE,1))),ABS(LOW-REF(CLOSE,1))),25); VVAR1:=SUM(MAX(MAX(HIGH-LOW,ABS(HIGH-REF(CLOSE,1))),ABS(LOW-REF(CLOSE,1))),25);VAR2:=HIGH-REF(HIGH,1);VAR3:=REF(LOW,1)-LOW;VAR4:=SUM(IF(VAR2>0 A =IF(AND(ROUND(MAX(SUM(B22,D22)),2)=0,ROUND(MIN(SUM(B22,D22)),2)=0),校验通过,校验失败) float aver=0.0,sum=0.0,*start,*p,max,min; int n,i=0;float aver=0.0,sum=0.0,*start,*p,max,min;这是完整的! 求大神指点这个公式错在哪里?IF(B5/(((D5+(SUM(B5:B12)-MAX(B5:B12)-MIN(B5:B12))/6)/2)*0.96)=1),40,IF(B5/(((D5+(SUM(B5:B12)-MAX(B5:B12)-MIN(B5:B12))/6)/2)*0.96)>1),40-((B5/(((D5+(SUM(B5:B12)-MAX(B5:B12)-MIN(B5:B12))/6)/2)*0.96))-1)*1,I 这个函数怎么理解?max(B5:G14)/SUM((B5:G14)) 有杭电ACM1006的解题思路吗求1006的解题思路,#includeint main(){int h,m,s,i,sum;float dh,dm,ds,d,max,mid,min,dd=0;while(scanf(%f,&d)!=EOF){if(d==-1) break;for(h=0,sum=0;h=d&&max-mid>=d&&(min+360-max)>=d)sum++; } printf(%.3f ,sum/(36* =IF(E10=,,SUBTOTAL(3,$E$10:E10))哪位朋友帮我解释一下这个函数公式,谢啦! max=a if(max