用Python寻找前n个质数output是这样:Find the first M prime numbers100 :3 is a prime number1 :5 is a prime number2 :7 is a prime number3 :11 is a prime number4 :13 is a prime number5 :17 is a prime number6 :19 is a prime number7 :23 is a pri

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用Python寻找前n个质数output是这样:Find the first M prime numbers100 :3 is a prime number1 :5 is a prime number2 :7 is a prime number3 :11 is a prime number4 :13 is a prime number5 :17 is a prime number6 :19 is a prime number7 :23 is a pri

用Python寻找前n个质数output是这样:Find the first M prime numbers100 :3 is a prime number1 :5 is a prime number2 :7 is a prime number3 :11 is a prime number4 :13 is a prime number5 :17 is a prime number6 :19 is a prime number7 :23 is a pri
用Python寻找前n个质数
output是这样:
Find the first M prime numbers
10
0 :3 is a prime number
1 :5 is a prime number
2 :7 is a prime number
3 :11 is a prime number
4 :13 is a prime number
5 :17 is a prime number
6 :19 is a prime number
7 :23 is a prime number
8 :29 is a prime number
9 :31 is a prime number

用Python寻找前n个质数output是这样:Find the first M prime numbers100 :3 is a prime number1 :5 is a prime number2 :7 is a prime number3 :11 is a prime number4 :13 is a prime number5 :17 is a prime number6 :19 is a prime number7 :23 is a pri
from itertools import count
from math import sqrt

def format_primes(fn):
    def add_descriptoin(n):
        primes = fn(n)
        for i, p in enumerate(primes):
            print("{} : {} is a prime number".format(i, p))
    return add_descriptoin

@format_primes
def first_primes(n):
    def prime_gen():
        primes = []
        for n in count(2):
            if all(n%p for p in primes if p <= sqrt(n)):
                primes.append(n)
                yield n
    primes = []
    for i, j in enumerate(prime_gen()):
        # if i < n:
        if i < (n+1):
            primes.append(j)
        else:
            break
    # return primes
    return primes[1:]

print("Find the first M prime numbers")
# python 2.x输入数据的话,要作相应修改
M = input("M? ")
first_primes(M)
按你的示例从3开始打印的,如果要从2开始用注释的两行替换这两行下面的行

用Python寻找前n个质数output是这样:Find the first M prime numbers100 :3 is a prime number1 :5 is a prime number2 :7 is a prime number3 :11 is a prime number4 :13 is a prime number5 :17 is a prime number6 :19 is a prime number7 :23 is a pri 求质数表前100个质数 python 在一个范围内,寻找另一个数字的所有整数倍数,并计算一共有多少个倍数这个是问题,真心不会做.我用的是python 2.7.要用 for loop1) 建立程序 count_multiples() which takes 三个非负整数:base,start an 用C++ 编写 阵列Description:根据读入的阶,按样例打印格式阵列.Input:输入数据含有不超过50个正整数n(1≤n≤25).Output:输出以n为阶的格式阵列.每个元素由一对括号和括号中的整数对组成,元素前 谁知道质数素数寻找 怎样寻找连续质数 用java根据输入第n个质数,能查出对应的数值?例如:1是第1个质数,2是第2个质数,3是第3个质数,5是第4质数 An表示前n个质数的和,求证:[An,An+1]中至少有一个完全平方数. VB 编写程序,请用户输入一个自然数N,求前N个质数,并将其存放一个数组中(质数是除了1和本身之外没有其他约数的数,第一个质数是2) VB 编写程序,请用户输入一个自然数N,求前N个质数,并将其存放一个数组中.(质数是除了1和本身之外没有其他约数的数,第一个质数是2) 1,2,3..,N这前N个自然数中,有p个质数,q个合数,m个奇数,n个偶数.试求(p-m)+(q-n)的值! 在1,2,3…,N这前N个自然数中,共有p个质数,q个合数,m个奇数,n个偶数,则(p-m)+(q-m)=_____. Output 在1,2,3.n这前n个自然数中,共有p个质数,q个合数,s个偶数,t个奇数,则(p-t)+(q-s)=?力求具体 自然数中的前10个质数是( ),前10个合数是( ),( )既不是质数,也不是合数. 一个七位数电话号码,它恰好是n个连续质数的乘积,这个积的末四位数的前三位数的10倍,这个 3个质数的和的导数为n/1001,求这3个质数 c++ sqrt 用函数Given natural number n.Calculate the expression shown on image using functions Example:Input:1 Output:1.41421 Example:Input:2 Output:1.84776