int a=5 double d=12345.6789 printf("%*.*lf\n",a+5,a-3,d) 请问答案是什么?

#includeusing namespace std;#define PI 314159double area(double radius=0);double area(double a,double b);double area(double a,double b,double h);double area(double a,double b,double c,int);int main(){cout int a=5 double d=12345.6789 printf(%*.*lf ,a+5,a-3,d) 请问答案是什么? 2.以下正确的函数定义是 .A）double fun(int x,int y) B）double fun(int x,y)所谓 { int z ; return z ;}C）fun (x,y) D）double fun (int x,int y){ int x,y ; double z ; { double z ;z=x+y ; return z ; } return z ; } 已知int a=2;double b=3.5;则a+b的值类型为什么?A.int B.double C.float D.以上答案都不对 double f(double x); {double a=0;int i; for (i=0;i 这个C++梯形法求定积分的函数为什么错了double tixing(double (*f)(double),double a,double b){int n=1000,i;double s,sum=0,d;d=(b-a)/n;double y1=(*f)(a+i*d);double y2=(*f)(a+i*d-d);for (i=1;i 牛顿迭代法求根,方程为ax^3+bx^2+cx+d=0的系数a,b,c,d为1 2 3 4求1附近的一个实根#include #include using namespace std; int main() { double newton(double a,double b,double c,double d,double x0); double a,b,c,d,x0; couta>>b>>c>>d; cou 下列方法定义中,正确的是（）A.int x(int a,b){return (a-b);}B.double x(int a,int b){int w; w=a-b;}C.int x(int a,int b){return a-b;}D.double x(a,b){return b;} 请高手帮忙解释下这段程序 int a;a=(int)((double)(3/2)+0.5+(int)1.99*2); printf(%d ,a);结果为3. 【c++】现有三个函数（1）double Add(double a) (2)double Add(double a,double b) (3)……如题,(3) int Add(double a,double b,double c=0)现在对Add函数进行调用,编译出现错误的是A.Add(3) B.Add(3.3,3.4) C.Add(2.3,3.1,3.2) D.Add(3 有关浮点数的运算程序A：double f(int x){ return 1.0 / x ; }void main(){ double a ,b;int i ;a = f(10) ;b = f(10) ;i = a == b ;printf( %d ,i ) ;}程序B：double f(int x){ return 1.0 / x ; }void main(){ double a ,b ,c;int i ;a = f(10) ;b operator=是什么意思啊# include double sum(double a,double b);double subtract(double a,double b);double divide(double a,double b);double multiply(double a,double b);main(){int choice;char operator;double a,b;double (*func)();printf( * * * * * c++中double x; int a; a=x=(a=5,5/2. C++题目看不懂,结果是怎么算出来的,#includeusing std::cin;using std::cout;using std::endl;float f1(int);float f2(int);double twice(float (*)(int),int);int main(){int a=3;int b=5;cout 以下的变量定义语句中,合法的是( ).A.float $_*5= 3.4F; B.double a =Double.MAX_VALUE; C.byte b1以下的变量定义语句中,合法的是( ).A.float $_*5= 3.4F; B.double a =Double.MAX_VALUE;C.byte b1= 15678; D.int _abc_ = 3721L;java语言 用高斯法求解方程int rgauss(int n,double a[],double b[]){int *js,l,k,i,j,is,p,q;double d,t;js=(int *)malloc(n*sizeof(int)); //开辟用于记忆列交换信息的动态空间l = 1; //置非奇异标志for(k=0;k int b(double l,double r) { double a; aint b(double l,double r){double a;a=(l+r)/2;if(a*a-6>0) b(l,a);else if(a*a-6 求下面的程序哪里出了问题.编写函数,根据整型形参m的指,计算如下公式 1-1/(2*2)-1/(3*3)-.-1/(m*m)#includestdio.hdouble fun(int m);main(){int a;scanf(%d,&a);printf(%lf ,fun(a));}double fun(int m){double sum,t;int i;sum=