已知(2sin^2α+2sinαcosα)/(1+tanα)=k(0

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已知(2sin^2α+2sinαcosα)/(1+tanα)=k(0

已知(2sin^2α+2sinαcosα)/(1+tanα)=k(0
已知(2sin^2α+2sinαcosα)/(1+tanα)=k(0

已知(2sin^2α+2sinαcosα)/(1+tanα)=k(0
(2sin^2 α+2sinα*cosα)/(1+tanα)=k (2sin^2 α+2sinα*cosα)/(1+tanα)=2sinacosa(sina+cosa)/(sina+cosa)=2sinacosa=k (sinα-cosα)^2=1-2sinacosa=1-k sinα-cosα=±√(1-k)