A={2x2-ax+b=0},B={bx2+(a+2)x+5+b=0},且A交B={2分之1},求A并B?急求,最迟今天晚上!还有一道英语题:短文改错 1.This is my first week in senior middle school.Now Iam 2.study in a new school and none my old friends3.have come to

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/14 04:38:40
A={2x2-ax+b=0},B={bx2+(a+2)x+5+b=0},且A交B={2分之1},求A并B?急求,最迟今天晚上!还有一道英语题:短文改错 1.This is my first week in senior middle school.Now Iam 2.study in a new school and none my old friends3.have come to

A={2x2-ax+b=0},B={bx2+(a+2)x+5+b=0},且A交B={2分之1},求A并B?急求,最迟今天晚上!还有一道英语题:短文改错 1.This is my first week in senior middle school.Now Iam 2.study in a new school and none my old friends3.have come to
A={2x2-ax+b=0},B={bx2+(a+2)x+5+b=0},且A交B={2分之1},求A并B?
急求,最迟今天晚上!
还有一道英语题:短文改错
1.This is my first week in senior middle school.Now Iam
2.study in a new school and none my old friends
3.have come to this school with me.I felt very lonely by the begginning.
4.But two days ago,I made friend with one of my new
5.classmates.His home was very close to the school,so he
6.can go home every day.He invited me have supper in
7.his home on yesterday.His mothor is a very kind-hearted
8.woman.She said that it was very importantly to have some
9.good friends in senior middle school.I am sure I will

A={2x2-ax+b=0},B={bx2+(a+2)x+5+b=0},且A交B={2分之1},求A并B?急求,最迟今天晚上!还有一道英语题:短文改错 1.This is my first week in senior middle school.Now Iam 2.study in a new school and none my old friends3.have come to
因为A交B=1/2,所以1/2是两个方程的公共根
代入方程得:1/2-1/2a+b=0,1-a+2b=0
1/2a+5/4b+6=0,2a+5b+24=0
所以a=-43/9 b=-26/9
所以集合A是18x^2+43x-26=0,集合B是-26x^2-25x+19=0,
用韦达定理,集合A中:x1+1/2=-43/18,1/2x1=-13/9
所以集合A是x1=-26/9,x2=1/2
同理:集合B是x1=-19/13,x2=1/2
所以A并B={x|x=1/2,-26/9,-19/13}

设a、b、c为正整数,ax^2+bx+c=0有两不等实根x1、x2,且|x1| 设a、b、c为正整数,ax^2+bx+c=0有两实根x1、x2,且|x1| 一元二次方程提ax^2+bx+c=0(a不等于0) 则有 x1+x2=-b/a x1*x2=c/a 设二次函数f(x)=ax²+bx+c(a≠0),若f(x1)=f(x2)(x1≠x2),则f(x1+x2)等于 (A)-b/2a(B)-b/a(C)c(D)4a 如果方程ax^2+bx+b=0中,a 若方程ax^2+bx+b=0中,a 设X1,X2是一元二次方程ax*2+bx+c=0的两个根,试推导x1+x2=-b/a,x1x2=c/a y=ax^2+bx+c(a>0),与x轴交于A(x1,0)B(x2,0)(x1<x2),则不等式ax^2+bx+c>0的解集为- 设二次函数f(x)=ax^2+bx+c(a≠0),若f(x1)=f(x2)(x1≠x2),则f(x1+x2)等于A.-b/2aB.-b/aC.cD.(4ac-b^2)/4a A:x1x2是方程ax^2+bx+c=0(a不等于0)的两实数根;B:x1+x2=-b/a,则A是B的什么条件?A:x1x2是方程ax^2+bx+c=0(a不等于0)的两实数根;B:x1+x2=-b/a,则A是B的什么条件? 一般情况下,如果一元二次方程ax^2+bx+c=0(a不等于0)的两个实数根分别为x1和x2,那么x1+x2=—b/a,x1乘x2一般情况下,如果一元二次方程ax^2+bx+c=0(a不等于0)的两个实数根分别为x1和x2,那么x1+x2=—b/a 设一元二次方程ax^2+bx+c=0的两个根为X1,X2,那么X1-X2=(√b^2-4ac)/a 已知a,b,c为正整数,方程ax^2+bx+c=0的两实根为x1,x2(x1≠x2)且|x1| 已知方程ax^2+bx+c=0的两根为x1,x2,且|x1|<1,|x2|<1,则a+b+c的最小值 已知非零向量a,b,c满足a⊥b,x1,x2是方程x*2+bx+c(x为实数)两根,求证x1=x2是ax^2+bx+c=0 已知x1,x2是关于x的一元二次方程ax^2+bx+c的两根,求证x1+x2=-b/a,x1*x2=c/a 若两个方程x2+ax+b=0和x2+bx+a=0有唯一公共解,则 a+b=? 若方程x2+ax+b=0和x2+bx+a=0只有一个公共根,则(a+b)200= .