作业帮已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1/2 若x∈[0,π/2已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1 若x∈[0,π/2],f(X)=根号3/3,求cosx的值（2）已知2bcosA≤2c-根号3a,求f（B）的
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![已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1/2 若x∈[0,π/2已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1 若x∈[0,π/2],f(X)=根号3/3,求cosx的值（2）已知2bcosA≤2c-根号3a,求f（B）的](/uploads/image/z/6831121-49-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8Fm%3D%28cosx%2F2%2C-1%29%2Cn%3D%28%E2%88%9A3sinx%2F2%2Ccosx%2F2%5E2%29+%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3Dm%C2%B7n%2B1%2F2+%E8%8B%A5x%E2%88%88%5B0%2C%CF%80%2F2%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8Fm%3D%28cosx%2F2%2C-1%29%2Cn%3D%28%E2%88%9A3sinx%2F2%2Ccosx%2F2%5E2%29+%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3Dm%C2%B7n%2B1+%E8%8B%A5x%E2%88%88%5B0%2C%CF%80%2F2%5D%2Cf%28X%29%3D%E6%A0%B9%E5%8F%B73%2F3%2C%E6%B1%82cosx%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E5%B7%B2%E7%9F%A52bcosA%E2%89%A42c-%E6%A0%B9%E5%8F%B73a%2C%E6%B1%82f%EF%BC%88B%EF%BC%89%E7%9A%84)
已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1/2 若x∈[0,π/2已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1 若x∈[0,π/2],f(X)=根号3/3,求cosx的值（2）已知2bcosA≤2c-根号3a,求f（B）的
已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1/2 若x∈[0,π/2
已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1 若x∈[0,π/2],f(X)=根号3/3,求cosx的值（2）已知2bcosA≤2c-根号3a,求f（B）的取值范围
已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1/2 若x∈[0,π/2已知向量m=(cosx/2,-1),n=(√3sinx/2,cosx/2^2) 设函数f(x)=m·n+1 若x∈[0,π/2],f(X)=根号3/3,求cosx的值（2）已知2bcosA≤2c-根号3a,求f（B）的
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