a[y-b/(2a)]^2+b[y-b/(2a)]+c=0怎么化简成a[y-b/(2a)]^2=ay^2-by+b^2/4a

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 04:29:31
a[y-b/(2a)]^2+b[y-b/(2a)]+c=0怎么化简成a[y-b/(2a)]^2=ay^2-by+b^2/4a

a[y-b/(2a)]^2+b[y-b/(2a)]+c=0怎么化简成a[y-b/(2a)]^2=ay^2-by+b^2/4a
a[y-b/(2a)]^2+b[y-b/(2a)]+c=0怎么化简成a[y-b/(2a)]^2=ay^2-by+b^2/4a

a[y-b/(2a)]^2+b[y-b/(2a)]+c=0怎么化简成a[y-b/(2a)]^2=ay^2-by+b^2/4a
用乘法公式(a-b)^2=a^2-2ab+b^2展开即可
a[y-b/(2a)]^2=a[y^2-2yb/2a+b^2/4a^2]=ay^2-by+b^2/4a

怎么没有C了