3/(x²-x)=6/(x²-1)-7/(x²+x)

3/(x²-x)=6/(x²-1)-7/(x²+x)
3/(x²-x)=6/(x²-1)-7/(x²+x)

3/(x²-x)=6/(x²-1)-7/(x²+x)
3/(x²-x)=6/(x²-1)-7/(x²+x)
3/x(x-1)=6/(x+1)(x-1)-7/x(x+1) 两边乘x(x+1)(x-1)
3(x+1)=6x-7(x-1)
3x+3=-x+7
3x+x=7-3
4x=4
x=1
由于x≠1
所以方程无解
如果本题有什么不明白可以追问,