1.[12-6y+( )]-[-5y^2-( )+( )]=2y^2+3y-42.已知x^2-xy=8,xy-y^2=3.则x^2-y=（ ）,x^2-y^2=( )a^3+a-4-( )=a^3-a^2+a

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1.[12-6y+( )]-[-5y^2-( )+( )]=2y^2+3y-42.已知x^2-xy=8,xy-y^2=3.则x^2-y=（ ）,x^2-y^2=( )a^3+a-4-( )=a^3-a^2+a

1.[12-6y+( )]-[-5y^2-( )+( )]=2y^2+3y-42.已知x^2-xy=8,xy-y^2=3.则x^2-y=（ ）,x^2-y^2=( )a^3+a-4-( )=a^3-a^2+a
1.[12-6y+( )]-[-5y^2-( )+( )]=2y^2+3y-4
2.已知x^2-xy=8,xy-y^2=3.则x^2-y=（ ）,x^2-y^2=( )
a^3+a-4-( )=a^3-a^2+a

1.[12-6y+( )]-[-5y^2-( )+( )]=2y^2+3y-42.已知x^2-xy=8,xy-y^2=3.则x^2-y=（ ）,x^2-y^2=( )a^3+a-4-( )=a^3-a^2+a
我直接填上了啊!
(1)[12-6y+(-3y^2)]-[-5y^2-(9y)+(16)]=2y^2+3y-4
(2)x^2-y^2=11
总的说,第1题答案是-3y^2 9y 16
第2题是11

[T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.') 解方程6y^2-12y-3+10y-2-6y^2,其中y=5/6 2y+5/3y-6-y/2=5y-4/2y-4 先化简,在求值：6y-(y+2分之y + 2-y分之y)除以y³-4y-2y²+8分之y,其中y= -2分之5先化简,在求值：6y-(y+2分之y + 2-y分之y)除以y³-4y-2y²+8分之y,其中y= -2分之5 用加减消元法解下列方程组,1.{9+2y=-1,9x-3y=92.11+5y=-28,2x+5y=-13.{8x-3y=12,2x+5y=264.{2x+3y=1,3x-5y=685.{6x+y=5,6x-y=3 1.{3x+2y=73x-4y+12 {x-6y=-23x+4y=53 {8x+3y+2=06x+5y+7=04 {2x-y=650%x+12.5%y=25%×35 {|x |+y=2|x |+2y=3希望可以有过程,用加减消元法谢谢了 计算.2x÷x/5x+3y^2-4y+4/2y-6·1/y+3÷12-6y/9-y^2 化简(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90) 1.试说明代数式(2y+3)(3y+2)-6y(y+3)+5y+16的值与y无关 y(5y-2)=6-4y 解方程 [2(x-y)^5-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2[2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2 -6y^2+7y+5因式分解 计算：[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1) 5/12[-3/4(x-y)^3]*(x+y)^2*(-x-y)^3*5/6(y-x)^2 y (3y^2+8y-3)-6y(3y+2y-1)+9y 解方程组：x+y/2+x-y/3=6 4(x+y)-5(x-y)=12 2(x-2y)²-7(x-2y)³+3(2y-x)²+(2y-x)³合并同类项 这个式子2（x-2y)²-7（x-2y)³+3(2y-x)²-(2y-x)³=2（x-2y)²-7（x-2y)³+3(x-2y)²+(x-2y)³=5(x-2y)²-6(x-2y)³=(x-2y)²(5-6x+12y) 若|x-2y+6|+(x+y+12)的2次方,求4x+5y