证明:cos( π/2n+1)+cos( 3π/2n+1)+cos( 5π/2n+1)+cos(7 π/2n+1)+...+cos[(2n-1) π/2n+1)]=1/2

来源:学生作业帮助网 编辑:作业帮 时间:2024/03/29 15:28:48
证明:cos( π/2n+1)+cos( 3π/2n+1)+cos( 5π/2n+1)+cos(7 π/2n+1)+...+cos[(2n-1) π/2n+1)]=1/2

证明:cos( π/2n+1)+cos( 3π/2n+1)+cos( 5π/2n+1)+cos(7 π/2n+1)+...+cos[(2n-1) π/2n+1)]=1/2
证明:cos( π/2n+1)+cos( 3π/2n+1)+cos( 5π/2n+1)+cos(7 π/2n+1)+...+cos[(2n-1) π/2n+1)]=1/2

证明:cos( π/2n+1)+cos( 3π/2n+1)+cos( 5π/2n+1)+cos(7 π/2n+1)+...+cos[(2n-1) π/2n+1)]=1/2
证明:
令S=cos( π/2n+1)+cos( 3π/2n+1)+cos( 5π/2n+1)+cos(7 π/2n+1)+...+cos[(2n-1) π/2n+1)],
则2sin(π/2n+1)×S = sin(2π/2n+1)+[sin(4π/2n+1)-sin(2nπ/2n+1)]+[sin(6π/2n+1)-sin(4π/2n+1)]+...
+{sin(2nπ/2n+1)-sin[(2n-2)π/2n+1]}
=sin2nπ/(2n+1)
得S=1/2