1/1乘2乘3+1/2乘3乘4+...+1/98乘99乘100=

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1/1乘2乘3+1/2乘3乘4+...+1/98乘99乘100=

1/1乘2乘3+1/2乘3乘4+...+1/98乘99乘100=
1/1乘2乘3+1/2乘3乘4+...+1/98乘99乘100=

1/1乘2乘3+1/2乘3乘4+...+1/98乘99乘100=
1/(1*2*3)+1/(2*3*4)+...+1/(98*99*100)
=(1/2)[1/(1*2)-1/(2*3)]+(1/2)[1/(2*3)-1/(3*4)]+...+(1/2)[1/(98*99)-1/(99*100)]
=(1/2)[1/(1*2)]-(1/2)[1/(2*3)]+(1/2)[1/(2*3)]-(1/2)[1/(3*4)]+...+(1/2)[1/(98*99)]-(1/2)[1/(99*100)]
中间的全部互相抵消,所以
=(1/2)[1/(1*2)]-(1/2)[1/(99*100)]
=4949/19800

1000

?=5145+2(1+1/2+1/3+1/4+1/5+...+1/98)=?,忘了分数怎么算了。