m²n²-2m²n+m²

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m²n²-2m²n+m²

m²n²-2m²n+m²
m²n²-2m²n+m²

m²n²-2m²n+m²
解 原式=m²(n²-2n)+m²
=m²(n²-2n+1)
=m²(n-1)²

=m²(n²-2n+1)
=m²(n-1)²

m²n²-2m²n+m²
=m²(n²-2n+1)
=m²(n-1)²

m²n²-2m²n+m²
=m^2(n^2-2n_1)
=m^2(n-1)^2

提出m²
所以 原式= m²(n²-2n+1)=m²(n-1)²