已知等差数列an的前n和sn=n^2+pn+q,且a2,a3,a5成等比数列 1)求p,q.的值.2)若bn满足an+log2n=log2bn,求bn的前n和Tn

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已知等差数列an的前n和sn=n^2+pn+q,且a2,a3,a5成等比数列 1)求p,q.的值.2)若bn满足an+log2n=log2bn,求bn的前n和Tn

已知等差数列an的前n和sn=n^2+pn+q,且a2,a3,a5成等比数列 1)求p,q.的值.2)若bn满足an+log2n=log2bn,求bn的前n和Tn
已知等差数列an的前n和sn=n^2+pn+q,且a2,a3,a5成等比数列 1)求p,q.的值.2)若bn满足an+log2n=log2bn,求bn的前n和Tn

已知等差数列an的前n和sn=n^2+pn+q,且a2,a3,a5成等比数列 1)求p,q.的值.2)若bn满足an+log2n=log2bn,求bn的前n和Tn
a1= p+q+1,
an = 2n+p-1 ,n≥2 ;
1) 由于{an}是等差数列,必有 p+q+1 = 2×1 +p-1,解得:q=0;
所以 a2= p+3,a3=p+5,a5=p+9 ,由等比数列解得:p= -1;
2) an = 2n-2,则 bn = n × 2^(2n-2) = n × 4^(n-1) ,
由错位相减法,解得 Tn = { (3n-1) × 4^n + 1 }/9 .