(x+y)(x+2y)(x+3y)(x+4y)=-40y的值为根号11

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(x+y)(x+2y)(x+3y)(x+4y)=-40y的值为根号11

(x+y)(x+2y)(x+3y)(x+4y)=-40y的值为根号11
(x+y)(x+2y)(x+3y)(x+4y)=-40
y的值为根号11

(x+y)(x+2y)(x+3y)(x+4y)=-40y的值为根号11
我把方法告诉你,最后的答案你自己做吧,很容易.
(x+y)(x+2y)(x+3y)(x+4y)=-40
(x+y)（x+4y）(x+2y)(x+3y）=-40
(x^2+5yx+44)(x^2+5yx+66)=-40
(x^2+5yx+44)(x^2+5yx+44+22)=-40
(x^2+5yx+44)^2+22(x^2+5yx+44)+40=0
设x^2+5yx+44=m,则原方程化为m^2+22m+40=0,解之得,m1=-20;m2=-2
于是有（1）x^2+5yx+44=-20（2）x^2+5yx+44=-2
把答案解出来即可,注意增根或不符合题意的未知数的值

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